How do you solve the following system using substitution?: $5x-y=3, 4y-x=1$

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How do you solve the following system using substitution?: $5x-y=3, 4y-x=1$

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Answer 1 · 2018-05-15T00:09:56

Solve one equation for one variable

Explanation:

Take one of the equations and solve for either x or y
$4y-x=1 => x=4y-1$

Plug into the other equation for x
$5(4y-1) - y = 3$

Solve
$20y-5-y=3$

$19y=8$

$y=8/19$

Plug y into original equation to find $x$

$4(8/19)-x=1$

$32/19 - x =1$

$x=13/19$

Answer 2 · 2018-05-15T00:16:05

$x=13/19$ and $y=8/19$

Explanation:

show below:

$5x-y=3$ ...............1

$4y-x=1$ ................2

from the equation 1

$y=5x-3$ .............3

put 3 in 2

$4(5x-3)-x=1$

$20x-12-x=1$

$19x=13$

$x=13/19$

$y=5(13/19)-3=65/19-3=[65-57]/19=8/19$

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How do you solve the following system using substitution?: $5x-y=3, 4y-x=1$

2 Answers

Explanation:

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How do you solve the following system using substitution?: $5x-y=3, 4y-x=1$