How do you solve $(3/4)x - (1/2)y = -(1/2)$ and $x + y = -(3/2)$ ?

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How do you solve $(3/4)x - (1/2)y = -(1/2)$ and $x + y = -(3/2)$ ?

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Answer 1 · 2018-06-26T14:48:22

Using substitution, we can find that $x=1$ and $y=-5/2$ .

Explanation:

Let's solve the second equation for one variable. We'll choose $x$ first:

$x=-3/2-y$

Let's now plug that into our first equation:

$3/4(-3/2-y)-1/2y=-1/2$
$-9/8-3/4y-1/2y=-1/2$
$-9/8-3/4y-2/4y=-1/2$
$-9/8-1/4y=-1/2$
$-1/4y=-1/2+9/8$
$-1/4y=-4/8+9/8$
$(-1/4y)/(-1/4)=(5/8)/(-1/4)$
$y=-5/2$

Let's now take our y-value and put that into our equations solved for $x$ :

$x=-3/2-(-5/2)$
$x=-3/2+5/2=2/2=1$

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How do you solve $(3/4)x - (1/2)y = -(1/2)$ and $x + y = -(3/2)$ ?

1 Answer

Explanation:

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How do you solve $(3/4)x - (1/2)y = -(1/2)$ and $x + y = -(3/2)$ ?