How do you solve $x - 2 y = 5$ $x - 2y =5$ and $2 x - 4 y = 1$ $2x -4y= 1$ using substitution?

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Answer 1 · 2016-06-28T23:33:23

No solutions. It is not possible $f or 2 x - 4 y = 1$ $for 2x -4y = 1$ and also at the same time, $2 x - 4 y = 10$ $2x - 4y = 10$

$x - 2 y = 5$ $x - 2y =5$ ======> 1

so, $x = 2 y + 5$ $x = 2y + 5$

$2 x - 4 y = 1$ $2x - 4y = 1$ ======> 2

substituting value of $x$ $x$ in 2, we get $2 \cdot (2 y + 5) - 4 y = 1$ $2*(2y+5) - 4y =1$

=> $cancel(4y) + 10 - cancel(4y) = 1$ => $10 = 1$ which is not TRUE.

Hence, No Solutions for the given equations.

How do you solve x - 2y =5x−2y=5x - 2y =5 and 2x -4y= 12x−4y=12x -4y= 1 using substitution?