How do you solve x+3y=1 and −3x−3y=−15 using substitution?
1 Answer
Apr 23, 2016
x=7
y=−2
Explanation:
Given_
x+3y=1 ---------------- (1)
−3x−3y=−15 -------------(2)
Solve Equation (1) for
x=1−3y
Substitutex=1−3y in equation (2)
−3(1−3y)−3y=−15
−3+9y−3y=−15
−3+6y=−15
6y=−15+3=−12
y=−126=−2
y=−2
Substitute
x+3(−2)=1
x−6=1
x=1+6=7
x=7