Question #4c8a8
1 Answer
Mar 18, 2017
Explanation:
We have the following equations.
xcolor(red)(+y)=10to(1)
color(red)(y)=4xto(2) Solve using the
color(blue)"substitution method" That is substitute
color(red)(y)=4x" into " (1)
rArrx+4x=10
rArr5x=10 divide both sides of the equation by 5
(cancel(5) x)/cancel(5)=10/5
rArrx=2 Substitute this value into ( 2 ) to obtain value for y
rArry=4xx2=8
color(blue)"As a check" Substitute these values into the original statements and if they are true then these are the solutions.
x+y=2+8=10to" True"
y=4xx2=8to" True"
rArrx=2" and "y=8" are the solution"