How do you solve the following system?: $3 x + 11 y = - 4, - 9 x + 5 y = 2$ $3x +11y =-4, -9x +5y = 2$

Question

How do you solve the following system?: $3 x + 11 y = - 4, - 9 x + 5 y = 2$ $3x +11y =-4, -9x +5y = 2$

1 Answer

Impact of this question

2815 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-26T10:17:23

$(x, y) = (- \frac{7}{19}, - \frac{5}{19})$ $(x,y)=(-7/19,-5/19)$

Explanation:

Solve by elimination:-

$3 x + 11 y = - 4, - 9 x + 5 y = 2$ $3x+11y=-4,-9x+5y=2$

It is possible to eliminate $- 9 x$ $-9x$ by $3 x$ $3x$ if we multiply $3 x$ $3x$ by $3$ $3$ to get $9 x$ $9x$

$\to 3 (3 x + 11 y = - 4)$ $rarr3(3x+11y=-4)$

$\to 9 x + 33 y = - 12$ $rarr9x+33y=-12$

Now add both of the equations:-

$\to (- 9 x + 5 y = 2) + (9 x + 33 y = - 12) = (38 y = - 10)$ $rarr(-9x+5y=2)+(9x+33y=-12)=(38y=-10)$

$\to 38 y = - 10$ $rarr38y=-10$

$\to y = - \frac{10}{38} = - \frac{5}{19}$ $rarry=-10/38=-5/19$

Now substitute the value of y to the first equation:-

$\to - 9 x + 5 (- \frac{5}{19}) = 2$ $rarr-9x+5(-5/19)=2$

$\to - 9 x - \frac{25}{19} = 2$ $rarr-9x-25/19=2$

$\to - 9 x = 2 + \frac{25}{19} = \frac{63}{19}$ $rarr-9x=2+25/19=63/19$

$\to x = \frac{63}{19} \div (- 9) = \frac{63}{19} \cdot (- \frac{1}{9}) = - \frac{63}{171} = - \frac{7}{19}$ $rarrx=63/19-:(-9)=63/19*(-1/9)=-63/171=-7/19$

So, $(x, y) = (- \frac{7}{19}, - \frac{5}{19})$ $(x,y)=(-7/19,-5/19)$

Science

Math

Humanities

... and beyond

How do you solve the following system?: $3 x + 11 y = - 4, - 9 x + 5 y = 2$ $3x +11y =-4, -9x +5y = 2$

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following system?: 3x +11y =-4, -9x +5y = 23x+11y=−4,−9x+5y=23x +11y =-4, -9x +5y = 2

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the following system?: $3 x + 11 y = - 4, - 9 x + 5 y = 2$ $3x +11y =-4, -9x +5y = 2$