How do you solve the following system?: $3x +11y =-4, -9x +5y = 2$

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Answer 1 · 2016-01-26T10:17:23

$(x,y)=(-7/19,-5/19)$

Solve by elimination:-

$3x+11y=-4,-9x+5y=2$

It is possible to eliminate $-9x$ by $3x$ if we multiply $3x$ by $3$ to get $9x$

$rarr3(3x+11y=-4)$

$rarr9x+33y=-12$

Now add both of the equations:-

$rarr(-9x+5y=2)+(9x+33y=-12)=(38y=-10)$

$rarr38y=-10$

$rarry=-10/38=-5/19$

Now substitute the value of y to the first equation:-

$rarr-9x+5(-5/19)=2$

$rarr-9x-25/19=2$

$rarr-9x=2+25/19=63/19$

$rarrx=63/19-:(-9)=63/19*(-1/9)=-63/171=-7/19$

So, $(x,y)=(-7/19,-5/19)$

How do you solve the following system?: 3x +11y =-4, -9x +5y = 23x +11y =-4, -9x +5y = 2