How do you solve the system of equations $2 x + 6 y = 14$ $2x + 6y = 14$ and $4 x = 16$ $4x = 16$ ?

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How do you solve the system of equations $2 x + 6 y = 14$ $2x + 6y = 14$ and $4 x = 16$ $4x = 16$ ?

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Answer 1 · 2017-05-12T02:31:14

Reduce each equation then substitute the second equation into the first equation. Answer: $(4, 1)$ $(4,1)$

Explanation:

Original equation: Given $2 x + 6 y = 14$ $2x+6y=14$ and $4 x = 16$ $4x=16$ , solve for $(x, y)$ $(x,y)$

We can solve this system of equations by using substitution. First, we can divide the first equation by $2$ $2$ and the second equation by $4$ $4$ :
$x + 3 y = 7$ $x+3y=7$
$x = 4$ $x=4$

Now, we simply substitute the second equation, $x = 4$ $x=4$ , into the first equation:
$4 + 3 y = 7$ $4+3y=7$
We can subtract $4$ $4$ from both sides to isolate the $3 y$ $3y$ :
$4 + 3 y - 4 = 7 - 4$ $4+3y-4=7-4$
$3 y = 3$ $3y=3$
Now, we divide both sides by $3$ $3$ to solve for $y$ $y$ :
$y = 1$ $y=1$

Therefore, our solution is the coordinate point $(4, 1)$ $(4,1)$

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How do you solve the system of equations $2 x + 6 y = 14$ $2x + 6y = 14$ and $4 x = 16$ $4x = 16$ ?

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Explanation:

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