How do you solve by substitution #6x + 2y = -2# and #4x + y = 1#?

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Answer 1 · 2018-03-20T06:44:52

#color(purple)(x = 2, y = -7#

#6x + 2y = -2#

#3x + y = -1 " Eqn (1)"# , dividing both sides by 2.

# y = -3x -1#

#4x + y = 1 " Eqn (2)"#

Substituting value of y in #"Eqn (2)#,

#4x + (-3x -1) = 1#

#4x - 3x -1 = 1#

#x = 1 + 1 = 2#

Substituting value of #x "in Eqn (1)#

#(3 * 2) + y = -1#

#y = -1 -6 = -7#