How do you solve by substitution $6 x + 2 y = - 2$ $6x + 2y = -2$ and $4 x + y = 1$ $4x + y = 1$ ?

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Answer 1 · 2018-03-20T06:44:52

$x = 2, y = - 7$ $color(purple)(x = 2, y = -7$

$6 x + 2 y = - 2$ $6x + 2y = -2$

$3 x + y = - 1 Eqn (1)$ $3x + y = -1 " Eqn (1)"$ , dividing both sides by 2.

$y = - 3 x - 1$ $y = -3x -1$

$4 x + y = 1 Eqn (2)$ $4x + y = 1 " Eqn (2)"$

Substituting value of y in $E q n (2)$ $"Eqn (2)$ ,

$4 x + (- 3 x - 1) = 1$ $4x + (-3x -1) = 1$

$4 x - 3 x - 1 = 1$ $4x - 3x -1 = 1$

$x = 1 + 1 = 2$ $x = 1 + 1 = 2$

Substituting value of $x \in E q n (1)$ $x "in Eqn (1)$

$(3 \cdot 2) + y = - 1$ $(3 * 2) + y = -1$

$y = - 1 - 6 = - 7$ $y = -1 -6 = -7$

How do you solve by substitution 6x + 2y = -26x+2y=−26x + 2y = -2 and 4x + y = 14x+y=14x + y = 1?