How do you solve #-5x - 4y = -48# and #-3x + 2y = 2 # using substitution?

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How do you solve #-5x - 4y = -48# and #-3x + 2y = 2 # using substitution?

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Answer 1 · 2016-03-12T18:46:05

#x=4#

Explanation:

#-5x-4y=-48" (1)"#
#-3x+2y=2 " "2y=2+3x " "color(green)(2*)2y=color(green)(2*)(2+3x)#
#color(red)(4y=4+6x)#
#"use (1)"#
#-5x-color(red)((4+6x))=-48#
#-5x-4-6x=-48#
#-11x=-48+4#
#-11x=-44#
#x=44/11#
#x=4#

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How do you solve #-5x - 4y = -48# and #-3x + 2y = 2 # using substitution?

1 Answer

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