How do you solve the following linear system: $3 x - 2 y = 7, x + 6 y = 12$ $3x-2y=7, x+6y=12$ ?

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Answer 1 · 2016-01-25T09:47:35

Multily the first equation by 3 and add to the second you get

$9 x + x - 6 y + 6 y = 21 + 12 \Rightarrow 10 x = 33 \Rightarrow x = \frac{33}{10}$ $9x+x-6y+6y=21+12=>10x=33=>x=33/10$

Replace the value of x to any of the intial equations to get

$y = \frac{29}{20}$ $y=29/20$

How do you solve the following linear system: 3x-2y=7, x+6y=123x−2y=7,x+6y=123x-2y=7, x+6y=12?