How do you solve #15x-20y=1# and #10y=1+5x# using substitution?

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How do you solve #15x-20y=1# and #10y=1+5x# using substitution?

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Answer 1 · 2016-08-15T14:49:35

#x=3/5# and #y=2/5#

Explanation:

We have two equations #15x-20y=1# and #10y=1+5x#. Here we can easily substitute the value of #10y# from the second equation into the first equation and doing so we get

#15x-20y=1#

#15x-2xx10y=1#

#15x-2×(1+5x)=1# or

#15x-2-10x=1# or

#15x-10x=1+2# or

#5x=3# and #x=3/5#.

Hence #10y=1+5x#

= #1+5×3/5=1+3=4# or

#y=4/10=2/5#

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How do you solve #15x-20y=1# and #10y=1+5x# using substitution?

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