How do you solve the following system: $x-4y=2, 3x-y=12$ ?

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How do you solve the following system: $x-4y=2, 3x-y=12$ ?

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Answer 1 · 2016-08-10T17:47:58

$x=46/11$
$y=6/11$ -

Explanation:

$x-4y=2$
or
$3x-12y=6$
Subtracting the equation $3x-12y=6$ from $3x-y=12$
we get
$3x-y-3x+12y=12-6$
or
$0+11y=6$
or
$11y=6$
or
$y=6/11$ -----------------------Ans $1$
By putting the value $y=6/11$ in the equation $x-4y=2$
we get
$x-4times6/11=2$
or
$x-24/11=2$
or
$x=2+24/11$
or
$x=46/11$ ------------------------------Ans $2$

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How do you solve the following system: $x-4y=2, 3x-y=12$ ?

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How do you solve the following system: x-4y=2, 3x-y=12 x-4y=2, 3x-y=12 ?

1 Answer

Explanation:

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How do you solve the following system: $x-4y=2, 3x-y=12$ ?