How do you solve the following linear system: $x - 6 y = 7, 5 x + 2 y = 10$ $x-6y= 7 , 5x+2y=10$ ?

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Answer 1 · 2015-12-02T20:03:12

$x = \frac{37}{16}$ $x=37/16$ , $y = - \frac{25}{32}$ $y=-25/32$

From the first equation, you have that $x = 6 y + 7$ $x=6y+7$ . Substitute this expression for $x$ $x$ in the second equation to have

$5 (6 y + 7) + 2 y = 10$ $5(6y+7)+2y=10$

$30 y + 35 + 2 y = 10$ $30y+35+2y=10$

$32 y = - 25$ $32y = -25$

$y = - \frac{25}{32}$ $y=-25/32$

Once $y$ $y$ is known, you can get $x$ $x$ from

$x = 6 y + 7 = 6 \cdot (- \frac{25}{32}) + 7 = \frac{37}{16}$ $x=6y+7 = 6*(-25/32)+7 = 37/16$

How do you solve the following linear system: x−6y=7,5x+2y=10x-6y= 7 , 5x+2y=10 ?