How do you solve the system of equations $50 x + 40 = y$ $50x + 40= y$ and $30 x + 45 = y$ $30x + 45= y$ ?

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Answer 1 · 2018-04-16T13:00:21

$x = 0.25, y = 52.5$ $x=0.25,y=52.5$

$:.50x+40=y------(1)$

$:.30x+45=y------(2)$

$:.(1)-(2)$

$:.20x-5=0$

$:.20x=5$

$:.x=cancel 5^1/cancel 20^4$

$:.x=1/4$ or $0.25$

substitute x=0.25 in (1)

$:.50(0.25)+40=y$

$:.12.5+40=y$

$:.y=52.5$

~~~~~~~~~~~~~~~

check:-

substitute $x=0.25$ and $y=52.5$ in $(2)$

$:.30(0.25)+45=52.5$

$:.7.5+45=52.5$

$:.52.5=52.5$

How do you solve the system of equations 50x + 40= y50x+40=y50x + 40= y and 30x + 45= y30x+45=y30x + 45= y?