How do you solve the following system?: $1/4x-3/7y=1 , 3/2x - 8y = 2$

Question

1651 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-14T12:07:03

$x = 24/19$ and $y = 14/19$

Given the system:

$1/4x - 3/7y = 1$

$3/2x - 8y = 2$

Multiply the first equation by $4$ to get:

$x - 12/7y = 4$

Add $12/7y$ to both sides to get:

$x = 12/7y+4$

Substitute this expression for $x$ in the second equation to get:

$2 = 3/2(12/7y+4)-8y$

$=18/7y+6-8y$

$=(18-56)/7y+6$

$=-38/7y+6$

Add $38/7y-2$ to both ends to get:

$38/7y = 4$

Multiply both sides by $7/38$ to get:

$y = 14/19$

Then we find:

$x = 12/7y+4 = 12/7(14/19)+4 = 24/19$

How do you solve the following system?: 1/4x-3/7y=1 , 3/2x - 8y = 2 1/4x-3/7y=1 , 3/2x - 8y = 2