How do solve the following linear system?: $y = 5 x - 7, y = 4 x + 4$ $y = 5x - 7, y = 4x + 4$ ?

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How do solve the following linear system?: $y = 5 x - 7, y = 4 x + 4$ $y = 5x - 7, y = 4x + 4$ ?

1 Answer

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Answer 1 · 2018-03-20T02:26:29

Notice that they both have $y$ $y$ by itself, so if you set them equal to each other you can solve for x. This makes sense if you consider that $y$ $y$ has the same value, and must be equal to itself.

Explanation:

$y = 5 x - 7 and y = 4 x + 4$ $y=5x-7 and y=4x+4$
$5 x - 7 = 4 x + 4$ $5x-7=4x+4$
Subtract $4 x$ $4x$ from both sides
$x - 7 = 4$ $x-7=4$
Add 7 to both sides
$x = 11$ $x=11$
$5 (11) - 7 = 48 = 4 (11) + 4$ $5(11)-7=48=4(11)+4$

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How do solve the following linear system?: $y = 5 x - 7, y = 4 x + 4$ $y = 5x - 7, y = 4x + 4$ ?

1 Answer

Explanation:

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How do solve the following linear system?: y = 5x - 7, y = 4x + 4 y=5x−7,y=4x+4 y = 5x - 7, y = 4x + 4 ?

1 Answer

Explanation:

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How do solve the following linear system?: $y = 5 x - 7, y = 4 x + 4$ $y = 5x - 7, y = 4x + 4$ ?