How do solve the following linear system?: $6 x + 3 y = 11, x + y = 6$ $6 x+3y=11 , x+y=6$ ?

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How do solve the following linear system?: $6 x + 3 y = 11, x + y = 6$ $6 x+3y=11 , x+y=6$ ?

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Answer 1 · 2016-02-10T03:34:44

$x = - \frac{7}{3}$ $x=-7/3$ , $y = \frac{25}{3}$ $y=25/3$

Explanation:

Please refer to some of my earlier replies. To solve a system of two linear equations in two variables you have to first eliminate one of variables.

The equations are $6 x + 3 y = 11$ $6x+3y=11$ and $x + y = 6$ $x+y=6$ .

Multiplying latter by 3 gives us $3 x + 3 y = 18$ $3x+3y=18$ .

Now subtracting first equation $6 x + 3 y = 11$ $6x+3y=11$ from $3 x + 3 y = 18$ $3x+3y=18$
gives us $3 x = - 7$ $3x=-7$ or $x = - \frac{7}{3}$ $x=-7/3$

Putting $x = - \frac{7}{3}$ $x=-7/3$ in $x + y = 6$ $x+y=6$ gives us

$y = 6 - x$ $y=6-x$ or $y = 6 - (- \frac{7}{3})$ $y=6-(-7/3)$ , which gives us

$y = \frac{25}{3}$ $y=25/3$

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How do solve the following linear system?: $6 x + 3 y = 11, x + y = 6$ $6 x+3y=11 , x+y=6$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do solve the following linear system?: 6x+3y=11,x+y=6 6 x+3y=11 , x+y=6 ?

1 Answer

Explanation:

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Impact of this question

How do solve the following linear system?: $6 x + 3 y = 11, x + y = 6$ $6 x+3y=11 , x+y=6$ ?