How do you solve the following linear system: $x+y=3, 3x + y = 4$ ?

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Answer 1 · 2018-03-25T05:00:16

$x=1/2$
$y=5/2$

Given -

$x+y=3$
$3x+y=4$

$x+y=3$ -------------(1)
$3x+y=4$ -------------(2) -----(1) $-$ (2)

$-2x=-1$
$x=(-1)/(-2)=1/2$

Substitute $x=1/2$ in equation (1)

$1/2+y=3$
$y=3-1/2=(6-1)/2=5/2$

How do you solve the following linear system: x+y=3, 3x + y = 4 x+y=3, 3x + y = 4 ?