How do you find the solution of the system of equations $y = x+1$ and $y = 2x -1$ ?

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Answer 1 · 2017-03-04T01:38:18

See the entire solution process below:

Step 1) Because the first equation is already solve for $y$ , substitute $x + 1$ for $y$ in the second equation and solve for $x$ :

$y = 2x - 1$ becomes:

$x + 1 = 2x - 1$

$x + 1 - color(red)(x) + color(blue)(1) = 2x - 1 - color(red)(x) + color(blue)(1)$

$x - color(red)(x) + 1 + color(blue)(1) = 2x - color(red)(x) - 1 + color(blue)(1)$

$0 + 2 = x - 0$

$2 = x$

$x = 2$

Step 2) Substitute $2$ for $x$ in the first equation and calculate $y$ :

$y = x + 1$ becomes:

$y = 2 + 1$

$y = 3$

The solution is: $x = 2$ and $y = 3$ or $(2, 3)$

How do you find the solution of the system of equations y = x+1y = x+1 and y = 2x -1y = 2x -1?