How do you solve #y= 3x+8# and #y=5x-10# using substitution?

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Answer 1 · 2016-03-09T13:56:07

The solution for the system of equations is:
#color(green)(x=9#
#color(green)(y=35#

#color(blue)(y=3x+8# .....equation #(1)#

#y=5x−10#....equation #(2)#

Solving by substitution:
Substituting equation #(1)# in #(2):#

#y=5x−10#

#color(blue)(3x+8)=5x−10#

#8+10=5x -3x#

#18=2x#

#x=18/2#

#color(green)(x=9#

Finding #y# from equation #(1):#
#y=3x+8#

#y=3 xx 9+8#

#y=27+8#

#color(green)(y=35#