How do you solve the following linear system #-4x - 3y = 5 , x - 4y = -3 #?

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Answer 1 · 2018-04-30T06:33:02

The solutions are #S={(x=-29/19),(y=7/19):}#

The system of equations are

#{(x-4y=-3),(-4x-3y=5):}#

#<=>#, #L2 larr (L2+4L1)#

#{(x-4y=-3),(0-19y=-7):}#

#<=>#, #L2larr((L2)/19)#

#{(x-4y=-3),(y=7/19):}#

#<=>#

#{(x=4*7/19-3=-29/19),(y=7/19):}#

#<=>#

#{(x=-29/19),(y=7/19):}#