How do you solve the following linear system $- 4 x - 3 y = 5, x - 4 y = - 3$ $-4x - 3y = 5 , x - 4y = -3$ ?

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Answer 1 · 2018-04-30T06:33:02

The solutions are $S={(x=-29/19),(y=7/19):}$

The system of equations are

${(x-4y=-3),(-4x-3y=5):}$

$<=>$ , $L2 larr (L2+4L1)$

${(x-4y=-3),(0-19y=-7):}$

$<=>$ , $L2larr((L2)/19)$

${(x-4y=-3),(y=7/19):}$

$<=>$

${(x=4*7/19-3=-29/19),(y=7/19):}$

$<=>$

${(x=-29/19),(y=7/19):}$

How do you solve the following linear system -4x - 3y = 5 , x - 4y = -3 −4x−3y=5,x−4y=−3-4x - 3y = 5 , x - 4y = -3 ?