How do you solve $3 w - 2 u = 12$ $3w-2u=12$ and $w - u = 60$ $w-u=60$ using substitution?

Question

How do you solve $3 w - 2 u = 12$ $3w-2u=12$ and $w - u = 60$ $w-u=60$ using substitution?

1 Answer

Impact of this question

1365 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-30T05:37:49

Solution is $w = - 108$ $w=-108$ and $u = - 168$ $u=-168$

Explanation:

To solve $3 w - 2 u = 12$ $3w-2u=12$ and $w - u = 60$ $w-u=60$

one has to find value of one variable in terms of another variable from one equation and then put it in other equation giving us value of another variable. This when put in first equation will give value of the other variable.

Here second equation $w - u = 60$ $w-u=60$ gives $w = 60 + u$ $w=60+u$ in terms of $u$ $u$ and putting this in first equation we get

$3 (60 + u) - 2 u = 12$ $3(60+u)-2u=12$

or $180 + 3 u - 2 u = 12$ $180+3u-2u=12$

or $u = 12 - 180 = - 168$ $u=12-180=-168$

Hence $w = 60 - 168 = - 108$ $w=60-168=-108$

Solution is $w = - 108$ $w=-108$ and $u = - 168$ $u=-168$

Science

Math

Humanities

... and beyond

How do you solve $3 w - 2 u = 12$ $3w-2u=12$ and $w - u = 60$ $w-u=60$ using substitution?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 3w−2u=123w-2u=12 and w−u=60w-u=60 using substitution?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $3 w - 2 u = 12$ $3w-2u=12$ and $w - u = 60$ $w-u=60$ using substitution?