How do solve the following linear system?: $- 8 x + y = 2, 3 x - 2 y = - 6$ $-8x + y = 2 , 3x - 2y = -6$ ?

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How do solve the following linear system?: $- 8 x + y = 2, 3 x - 2 y = - 6$ $-8x + y = 2 , 3x - 2y = -6$ ?

1 Answer

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Answer 1 · 2018-07-15T01:58:33

$y = 3 \frac{3}{13}$ $y=3 3/13$
$x = \frac{2}{13}$ $x=2/13$

Explanation:

$- 8 x + y = 2$ $-8x+y=2$ --- (1)
$3 x - 2 y = - 6$ $3x-2y=-6$ --- (2)

From (1),
$- 8 x + y = 2$ $-8x+y=2$
$y = 2 + 8 x$ $y=2+8x$ --- (3)

Sub (3) into (2)
$3 x - 2 y = - 6$ $3x-2y=-6$
$3 x - 2 (2 + 8 x) = - 6$ $3x-2(2+8x)=-6$
$3 x - 4 - 16 x = - 6$ $3x-4-16x=-6$
$- 13 x - 4 = - 6$ $-13x-4=-6$
$- 13 x = - 2$ $-13x=-2$
$x = \frac{2}{13}$ $x=2/13$ --- (4)

Sub (4) into (3)
$y = 2 + 8 x$ $y=2+8x$
$y = 2 + 8 \times \frac{2}{13}$ $y=2+8times2/13$
$y = 3 \frac{3}{13}$ $y=3 3/13$

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How do solve the following linear system?: $- 8 x + y = 2, 3 x - 2 y = - 6$ $-8x + y = 2 , 3x - 2y = -6$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do solve the following linear system?: −8x+y=2,3x−2y=−6 -8x + y = 2 , 3x - 2y = -6 ?

1 Answer

Explanation:

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Impact of this question

How do solve the following linear system?: $- 8 x + y = 2, 3 x - 2 y = - 6$ $-8x + y = 2 , 3x - 2y = -6$ ?