How do solve the following linear system?: 3x-8y=6, 5x+2y=2 ?

1 Answer
Jumbotron
Apr 18, 2018

See a solution process below

Explanation:

3x - 8y = 6 - - - eqn1

5x + 2y = 2 - - - eqn2

Using elimination method..

5 xx (3x - 8y = 6)

3 xx (5x + 2y = 2)

15x - 40y = 30 - - - eqn3

15x - 6y = 6 - - - eqn4

Subtract eqn3 and eqn4

-34y = 24

y = - 24/34

y = - 12/17

Substitute the value of y into eqn1

3x - 8y = 6

3x - 8(-12/17) = 6

3x + 96/17 = 6

Multiply through by 17

17(3x) + 17(96/17) = 17(6)

51x + 96 = 102

51x = 102 - 96

51x = 6

x = 6/51

x = 2/17

Hence;

x = 2/17 and y = -12/17

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