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Answer 1 · 2016-08-17T20:40:43

$x = 52, a = 39$ $x = 52, a = 39$

If you have equations which have fractions, you can get rid of the denominators by multiplying each term by the LCD

$\frac{x}{8} - \frac{1}{2} = 6 L C D = 8$ $x/8 -1/2 = 6 " " LCD = 8$

$\frac{8 \times x}{8} - \frac{8 \times 1}{2} = 8 \times 6$ $(color(red)8 xx x)/8 -(color(red)8 xx 1)/2 = color(red)8 xx 6$

$(color(red)cancel8 xx x)/cancel8 -(color(red)cancel8^4 xx 1)/cancel2 = color(red)8 xx 6$

$x-4 = 48$

$x = 52$

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$15= a/3 -2" "xx3$

$color(blue)3xx15= (color(blue)(cancel3xx)a)/cancel3 - color(blue)(3xx)(-2)$

$45 = a +6$

$39 = a$