How do you solve the following system?: $-6x -3y =1, -2x +4y = -5$

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How do you solve the following system?: $-6x -3y =1, -2x +4y = -5$

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Answer 1 · 2016-02-07T18:35:12

$x =11/30,y = -16/15$

Explanation:

We have the equations:
$-6x-3y=1$ and
$-2x+4y=-5$

I would say the best way to procede is to eliminate the $x$ terms. Multiply the 2nd equation by 3 so that the coefficient of $x$ on the 2nd equation is the same as the coefficient of $x$ on the first equation giving:

That means the 2nd equation becomes:

$-6x+12y=-15$

Now subtract the equations from each other to eliminate the $x$ terms and get:

$(-6x-3y)-(-6x+12y) = 1 - (-15)$
$-> -15y = 16 -> y = -16/15$

Now put this value of $y$ back into either of the original equations to find $x$ , we'll choose the first equation:

$-6x -3(-16/15) = 1$
$-6x +16/5 = 1$
$-> -6x = 1-16/5=-11/5$
Thus:
$x =11/30$

Hence our final solution. It is good practice to put these values into the other equation to check that they work.

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How do you solve the following system?: $-6x -3y =1, -2x +4y = -5$

1 Answer

Explanation:

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How do you solve the following system?: -6x -3y =1, -2x +4y = -5-6x -3y =1, -2x +4y = -5

1 Answer

Explanation:

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How do you solve the following system?: $-6x -3y =1, -2x +4y = -5$