How do you solve the following linear system: $2 x - y = 2, 6 x - y = - 2$ $2x-y=2, 6x-y= -2$ ?

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How do you solve the following linear system: $2 x - y = 2, 6 x - y = - 2$ $2x-y=2, 6x-y= -2$ ?

1 Answer

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Answer 1 · 2015-12-30T11:32:55

By substitution $x = - 1, y = - 4$ $x = -1, y = -4$

Explanation:

Rearrange one of the expressions to get y on its own on the LHS, then substitute in the other equation.
$y = 2 x - 2$ $y = 2x - 2$
Then $6 x - (2 x - 2) = - 2$ $6x -(2x-2) = -2$
4x = -4x=-1#

Then $y = 2 (- 1) - 2 = - 4$ $y = 2(-1) - 2 = -4$

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How do you solve the following linear system: $2 x - y = 2, 6 x - y = - 2$ $2x-y=2, 6x-y= -2$ ?

1 Answer

Explanation:

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How do you solve the following linear system: $2 x - y = 2, 6 x - y = - 2$ $2x-y=2, 6x-y= -2$ ?