Solve by elimination and substitution
1)color(blue)(-2x+5y=-3
2)color(blue)(x-3y=-2
If you see carefully, you could eliminate -2x from the first equation by x in the second equation if we multiply x with 2 to get 2x
rarr2(x-3y=-2)
Use distributive property color(brown)(a(b+c=d),ab+ac=ad
rarr2x-6y=-4
Now, add both of the equations
rarr(-2x+5y=-3)+(2x-6y=-4)
rarr-y=-7
rArrcolor(green)(y=7
Substitute the value of y to the first equation
rarr-2x+5(7)=-3
rarr-2x+35=-3
rarr-2x=-3-35
rarr-2x=-38
rArrcolor(green)(x=(-38)/-2=38/2=19
Check (Substitute the values of x and y to the first equation)
color(orange)(-2(19)+5(7)=-3
color(orange)(-38+35=-3
color(orange)(-3=-3 =) correct!
Now to the second equation
color(indigo)(19-3(7)=-2
color(indigo)(19-21=-2
color(indigo)(-2=-2 :) correct!
**:. x and y have values of 19 and 7 **
