How do you solve $x-2y=-1$ and $2x-y=4$ using substitution?

Question

How do you solve $x-2y=-1$ and $2x-y=4$ using substitution?

1 Answer

Impact of this question

3961 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-01T01:04:52

$x = 3 and = 2$

Explanation:

$x - 2y = -1 - - - eqn1$

$2x - y = 4 - - - eqn2$

Using Substitution Method..

From $eqn1$

$x - 2y = -1 - - - eqn1$

Making $x$ the subject of formula;

$x - 2y = -1$

$x = -1 + 2y$

$x = 2y - 1 - - - eqn3$

Substitute $eqn3$ into $eqn2$

$2x - y = 4 - - - eqn2$

$2(2y - 1) - y = 4$

$4y - 2 - y = 4$

$4y - y - 2 = 4$

$3y - 2 = 4$

$3y = 4 + 2$

$3y = 6$

$y = 6/3$

$y = 2$

Substituting the value of $y$ into $eqn3$

$x = 2y - 1 - - - eqn3$

$x = 2(2) - 1$

$x = 4 - 1$

$x = 3$

Therefore;

$x = 3 and = 2$

Science

Math

Humanities

... and beyond

How do you solve $x-2y=-1$ and $2x-y=4$ using substitution?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve x-2y=-1x-2y=-1 and 2x-y=42x-y=4 using substitution?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $x-2y=-1$ and $2x-y=4$ using substitution?