How do you solve (x + 2)/2 = (y + 18)/4 and x/3 = (2y + 4)/6?

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Answer 1 · 2018-07-06T17:19:43

$x = 12, y = 10$ $x=12,y=10$

Multiplying the second equation by $3$ $3$

$x = \frac{3}{6} \cdot (2 y + 4) = \frac{2 y + 4}{2} = y + 2$ $x=3/6*(2y+4)=(2y+4)/2=y+2$

and multiplying the fist equation by $4$ $4$

$2 (x + 2) = y + 18$ $2(x+2)=y+18$
multiplying out

$2 x + 4 = y + 18$ $2x+4=y+18$
adding $- 4$ $-4$

$2 x = y + 14$ $2x=y+14$
plugging the equation above ( $x = y + 2$ $x=y+2$ )

in this equation

$2 y + 4 = y + 14$ $2y+4=y+14$

adding $- 4$ $-4$ and $- y$ $-y$

$y = 10$ $y=10$

so $x = 12$ $x=12$