How do you solve 3x + y = 1 and y + 4 = 5x using substitution?

1 Answer
Aug 27, 2017

See a solution process below: (5/8, -7/8)

Explanation:

Step 1)* Solve the second equation for y:

y + 4 = 5x

y + 4 - color(red)(4) = 5x - color(red)(4)

y + 0 = 5x - 4

y = 5x - 4

Step 2) Substitute (5x - 4) for y in the first equation and solve for x:

3x + y = 1 becomes:

3x + (5x - 4) = 1

3x + 5x - 4 = 1

(3 + 5)x - 4 = 1

8x - 4 = 1

8x - 4 + color(red)(4) = 1 + color(red)(4)

8x - 0 = 5

8x = 5

(8x)/color(red)(8) = 5/color(red)(8)

(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = 5/8

x = 5/8

**Step 3) Substitute 5/8 for x in the solution to the second equation at the end of Step 1 and calculate y#:

y = 5x - 4 becomes:

y = (5 xx 5/8) - 4

y = 25/8 - 4

y = 25/8 - (8/8 xx 4)

y = 25/8 - 32/8

y = (25 - 32)/8

y = -7/8

The Solution Is: x = 5/8 and y = -7/8 or (5/8, -7/8)