How do you solve the following system?: $5x +3y =7, 91x +56y = 0$

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Answer 1 · 2018-06-21T08:48:55

$color(purple)(x = 56, y = -91$

$5x + 3y = 7, " Eqn (1)"$

$280x + 168y = 392, "Eqn (1) * 56"$

$91x + 56y = 0. "Eqn (2)"$

$273x + 168y = 0, " Eqn (2) * 3"$

$56 * " Eqn (1)" - 3 * " Eqn (2)"$ ,

$280x - 273x = 392$

$x = 392/7 = 56$

Substituting value of x in Eqn (1),

$280 + 3y = 7$

$3y = -273 " or " y = -91$

How do you solve the following system?: 5x +3y =7, 91x +56y = 05x +3y =7, 91x +56y = 0