How do you solve the following system?: #5x +3y =7, 91x +56y = 0#

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Answer 1 · 2018-06-21T08:48:55

#color(purple)(x = 56, y = -91#

#5x + 3y = 7, " Eqn (1)"#

#280x + 168y = 392, "Eqn (1) * 56"#

#91x + 56y = 0. "Eqn (2)"#

#273x + 168y = 0, " Eqn (2) * 3"#

#56 * " Eqn (1)" - 3 * " Eqn (2)"#,

#280x - 273x = 392#

#x = 392/7 = 56#

Substituting value of x in Eqn (1),

#280 + 3y = 7#

#3y = -273 " or " y = -91#