How do you solve the following system: #-x+6y=12 , 2x-y=7 #?

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Answer 1 · 2017-03-22T20:22:39

#x=54/11, y=31/11#

#2x-y=7#
#-x+6y=12 (*2)#

#2x-y=7#
#-2x+12y=24#

add together:

#(0+)11y=31#
#11y=31#
#y=31/11 or 2 9/11#

#2x-y=7#
#2x - 2 9/11 = 7#

add #2 9/11#:

#2x = 9 9/11 or 108/11#

divide by 2:
#x = 54/11#

#x=54/11, y=31/11#