How do you solve the following system: $-x+6y=12 , 2x-y=7$ ?

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Answer 1 · 2017-03-22T20:22:39

$x=54/11, y=31/11$

$2x-y=7$
$-x+6y=12 (*2)$

$2x-y=7$
$-2x+12y=24$

add together:

$(0+)11y=31$
$11y=31$
$y=31/11 or 2 9/11$

$2x-y=7$
$2x - 2 9/11 = 7$

add $2 9/11$ :

$2x = 9 9/11 or 108/11$

divide by 2:
$x = 54/11$

$x=54/11, y=31/11$

How do you solve the following system: -x+6y=12 , 2x-y=7 -x+6y=12 , 2x-y=7 ?