How do you solve the following system: $- x + 6 y = 12, 3 x + 4 y = - 10$ $-x+6y=12, 3x+4y=-10$ ?

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How do you solve the following system: $- x + 6 y = 12, 3 x + 4 y = - 10$ $-x+6y=12, 3x+4y=-10$ ?

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Answer 1 · 2016-09-08T13:04:04

$x = - \frac{54}{11}$ $x=-54/11$

$y = \frac{13}{11}$ $y=13/11$

Explanation:

$- x + 6 y = 12$ $-x+6y=12$ and $3 x + 4 y = - 10$ $3x+4y=-10$

or

$x = 6 y - 12$ $x=6y-12$

or

$x = 6 (y - 2)$ $x=6(y-2)$

Multiplying $- x + 6 y = 12$ $-x+6y=12$ by $3$ $3$

We get

$- 3 x + 18 y = 36$ $-3x+18y=36$

By adding $- 3 x + 18 y = 36$ $-3x+18y=36$ with $3 x + 4 y = - 10$ $3x+4y=-10$

We get

$- 3 x + 18 y + 3 x + 4 y = 36 - 10$ $-3x+18y+3x+4y=36-10$

or

$22 y = 26$ $22y=26$

or

$y = \frac{26}{22}$ $y=26/22$

or

$y = \frac{13}{11}$ $y=13/11$ ----------------------Ans $1$ $1$

By plugging the value $y = \frac{13}{11}$ $y=13/11$ in the equation $x = 6 (y - 2)$ $x=6(y-2)$

We get

$x = 6 (\frac{13}{11} - 2)$ $x=6(13/11-2)$

or

$x = 6 \times \frac{13 - 22}{11}$ $x=6 times (13-22)/11$

or

$x = 6 \times (- \frac{9}{11})$ $x=6times (-9/11)$

or

$x = - \frac{54}{11}$ $x=-54/11$ ---------------------Ans $2$ $2$

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How do you solve the following system: $- x + 6 y = 12, 3 x + 4 y = - 10$ $-x+6y=12, 3x+4y=-10$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following system: −x+6y=12,3x+4y=−10-x+6y=12, 3x+4y=-10 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following system: $- x + 6 y = 12, 3 x + 4 y = - 10$ $-x+6y=12, 3x+4y=-10$ ?