How do you solve the following system: $2 x + 3 y = 22, 5 x - 2 y = - 26$ $2x+3y=22, 5x-2y=-26$ ?

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Answer 1 · 2017-07-03T13:39:24

$(x, y) \in {(- \frac{34}{19}, \frac{162}{19})}$ $(x,y) in { (-34/19, 162/19) }$

$4 x + 6 y = 44 and 15 x - 6 y = - 78$ $4x + 6y = 44 and 15x - 6y = -78$

Sum: $19 x = 44 - 78 \Rightarrow x = - \frac{34}{19}$ $19x = 44 - 78 => x = -34/19$

$- 5 \cdot \frac{34}{19} + 26 = 2 y \Rightarrow y = - \frac{85}{19} + 13 = \frac{162}{19}$ $-5*34/19 + 26 = 2y => y = -85/19+13 = 162/19$

How do you solve the following system: 2x+3y=22, 5x-2y=-26 2x+3y=22,5x−2y=−262x+3y=22, 5x-2y=-26 ?