How do you solve the following system?: -x -2y =-1, 3x -y = -4

1 Answer
Mar 2, 2018

The point of intersection is (-1,1).

Explanation:

Solve system:

color(blue)("Equation 1:" -x-2y=-1

color(green)("Equation 2:" 3x-y=-4

The given equations are linear equation in standard form. I will show how to solve this system of equations using substitution. The resulting point (x,y) is the point of intersection between the lines.

Solve Equation 1 for x.

-x-2y=-1

Subtract 2y from both sides of the equation.

-x=2y-1

Multiply both sides by -1.

x=-2y+1=

x=color(red)(1-2y

Substitute color(red)(1-2y for x in Equation 2 and solve for y.

3(color(red)(1-2y))-y=-4

Expand.

3-6y-y=-4

Subtract 3 from both sides.

-6y-y=-4-3

Simplify.

-7y=-7

Divide both sides by -7.

y=(color(red)cancel(color(black)(-7)))^1/(color(red)cancel(color(black)(-7)))^1

y=color(teal)1

Substitute color(teal)1 for y in Equation 1.

-x-2(color(teal)(1))=-1

Simplify.

-x-2=-1

Add 2 to both sides.

-x=-1+2

Simplify.

-x=1

Multiply both sides by -1.

x=-1

Point of intersection : (-1,1)

graph{(-2y-x+1)(-y+3x+4)=0 [-10, 10, -5, 5]}