How do you solve the following system: $3x+y=8, -x+6y=12$ ?

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Answer 1 · 2018-03-23T11:58:32

Arrange the equations

$3x + y = 8$
$-3x + 18y = 36$

After expanding the 2nd equation by 3. Sum these up:

$19 y = 44$

$y = 44/19$

Put this value into the first original equation:

$3x = 8 - 44/19$

$3x = (152-44)/19$

$3x = 108/19$

$x = 108/57$

$x =36/19$

How do you solve the following system: 3x+y=8, -x+6y=12 3x+y=8, -x+6y=12 ?