How do you solve the following equations by substitution?: #5x - 2y = -5# and #y - 5x = 3#?

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Answer 1 · 2018-05-09T04:20:32

#color(indigo)(x = -1/5, y = 2#

#5x - 2y = -5, " Eqn (1)#

#5x = 2y - 5#

#x = (2y - 5) / 5#

#-5x + y = 3, " Eqn (2)#

Substituting value of x in terms of y in Eqn (2),

#((-5 * (2y - 5)) / 5) + y = 3#

#-2y + 5 + y = 3#

#-2y + y = 3 - 5#

#color(indigo)(y = 2#

Substituting value of y in Eqn (1),

#5x - 4 =- 5#

#color(indigo)(x = -1/5#