How do you solve the following equations by substitution?: $5 x - 2 y = - 5$ $5x - 2y = -5$ and $y - 5 x = 3$ $y - 5x = 3$ ?

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Answer 1 · 2018-05-09T04:20:32

$x = - \frac{1}{5}, y = 2$ $color(indigo)(x = -1/5, y = 2$

$5 x - 2 y = - 5, E q n (1)$ $5x - 2y = -5, " Eqn (1)$

$5 x = 2 y - 5$ $5x = 2y - 5$

$x = \frac{2 y - 5}{5}$ $x = (2y - 5) / 5$

$- 5 x + y = 3, E q n (2)$ $-5x + y = 3, " Eqn (2)$

Substituting value of x in terms of y in Eqn (2),

$(\frac{- 5 \cdot (2 y - 5)}{5}) + y = 3$ $((-5 * (2y - 5)) / 5) + y = 3$

$- 2 y + 5 + y = 3$ $-2y + 5 + y = 3$

$- 2 y + y = 3 - 5$ $-2y + y = 3 - 5$

$y = 2$ $color(indigo)(y = 2$

Substituting value of y in Eqn (1),

$5 x - 4 = - 5$ $5x - 4 =- 5$

$x = - \frac{1}{5}$ $color(indigo)(x = -1/5$

How do you solve the following equations by substitution?: 5x−2y=−55x - 2y = -5 and y−5x=3y - 5x = 3?