How do you solve $2x + 5y = 2$ and $-3x - y = -3$ using substitution?

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Answer 1 · 2018-06-23T09:40:32

$x=1$ and $y=0$

From second equation, $y=3-3x$

After putting value into first one,

$2x+5*(3-3x)=2$

$2x+15-15x=2$

$15-13x=2$

$-13x=-13$ , so $x=(-13)/(-13)=1$

Thus $y=3-3*1=0$

How do you solve 2x + 5y = 22x + 5y = 2 and -3x - y = -3-3x - y = -3 using substitution?