How do you solve the system of equations by substitution $y = - 2$ $y= -2$ and $4 x - 3 y = 18$ $4x - 3y =18$ ?

Question

10288 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-09T01:45:18

$x = 3, y = - 2$ $x=3,y=-2$

Substitute the given $y$ $y$ -value into $4 x - 3 y = 18$ $4x-3y=18$ and solve for $x$ $x$

If $y = - 2$ $y=-2$ then,

$4 x - 3 (- 2) = 18$ $4x-3(-2)=18$

$4 x + 6 = 18$ $4x+6=18$

$4x+cancel(6-6)=18-6$

$4x=12$

$cancel(4/4)x=12/4$

$x=3$

The solution to the system of equations is thus: $x=3,y=-2$

How do you solve the system of equations by substitution y= -2y=−2y= -2 and 4x - 3y =184x−3y=184x - 3y =18?