How do you solve the following system: $y = 3x – 12, x = 4 – 2y$ ?

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How do you solve the following system: $y = 3x – 12, x = 4 – 2y$ ?

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Answer 1 · 2018-04-21T16:04:08

$x=4, y=0$

Explanation:

First substitute $x=4-2y$ into $y=3x-12$
Then the equation becomes:
$y=3(4-2y)-12$
$y=12-6y-12$
bring all the $y$ to the LHS:
$7y=0$
$y=0$
Then substitute $y=0$ into $x=4-2y$
$x=4-2(0)$
$x=4$

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How do you solve the following system: $y = 3x – 12, x = 4 – 2y$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system: y = 3x – 12, x = 4 – 2y y = 3x – 12, x = 4 – 2y ?

1 Answer

Explanation:

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How do you solve the following system: $y = 3x – 12, x = 4 – 2y$ ?