Question #dfe7b
1 Answer
Mar 24, 2017
Explanation:
Label the equations.
color(red)(y)=-2x+6to(1)y=−2x+6→(1)
color(red)(y)=x-3to(2)y=x−3→(2) Since both equation have y as the subject we can equate the right sides.
rArrx-3=-2x+6⇒x−3=−2x+6 add 2x to both sides.
x+2x-3=cancel(-2x)cancel(+2x)+6
rArr3x-3=6 add 3 to both sides.
3xcancel(-3)cancel(+3)=6+3
rArr3x=9 divide both sides by 3
(cancel(3) x)/cancel(3)=9/3
rArrx=3 Substitute this value into either of the 2 equations.
"Substitute "x=3" in " (2)
x=3toy=3-3=0
color(blue)"As a check"
"Substitute " x=3" in " (1)
x=3to(-2xx3)+6=-6+6=0to" true"
rArr(3,0)" is the point of intersection"
graph{(y+2x-6)(y-x+3)=0 [-10, 10, -5, 5]}
