How do solve the following linear system?: $x + 3 y = 9, y = - 2 x + 1$ $x + 3y = 9 , y= -2x + 1$ ?

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How do solve the following linear system?: $x + 3 y = 9, y = - 2 x + 1$ $x + 3y = 9 , y= -2x + 1$ ?

1 Answer

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Answer 1 · 2018-05-28T12:46:23

$x = - \frac{6}{5}, y = \frac{17}{5}$ $x=-6/5,y=17/5$

Explanation:

Plugging
$y = - 2 x + 1$ $y=-2x+1$ in the first equation we get
$x + 3 (- 2 x + 1) = 9$ $x+3(-2x+1)=9$
so
$x - 6 x + 3 = 9$ $x-6x+3=9$
$- 5 x + 3 = 9$ $-5x+3=9$
$- 5 x = 6$ $-5x=6$
$x = - \frac{6}{5}$ $x=-6/5$
so
$y = \frac{12}{5} + \frac{5}{5} = \frac{17}{5}$ $y=12/5+5/5=17/5$

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How do solve the following linear system?: $x + 3 y = 9, y = - 2 x + 1$ $x + 3y = 9 , y= -2x + 1$ ?

1 Answer

Explanation:

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How do solve the following linear system?: x + 3y = 9 , y= -2x + 1 x+3y=9,y=−2x+1 x + 3y = 9 , y= -2x + 1 ?

1 Answer

Explanation:

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How do solve the following linear system?: $x + 3 y = 9, y = - 2 x + 1$ $x + 3y = 9 , y= -2x + 1$ ?