How do you solve the following system?: $- x + 6 y = - 2, 5 x - 2 y = 3$ $-x+6y= - 2 , 5x - 2y= 3$

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How do you solve the following system?: $- x + 6 y = - 2, 5 x - 2 y = 3$ $-x+6y= - 2 , 5x - 2y= 3$

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Answer 1 · 2017-05-07T23:17:24

Make the first equation $x = 6 y + 2$ $x=6y+2$ and substitute into the second equation.

Explanation:

By adding x and 2 to both sides of the first equation, we get:
$x = 6 y + 2$ $x=6y+2$
Now we substitute this expression of x into the second equation to get:
$5 (6 y + 2) - 2 y = 3$ $5(6y+2)-2y=3$ which we can distribute the 5 on the left hand side to get:
$30 y + 10 - 2 y = 3$ $30y+10-2y=3$ which we combine the y-terms on the left hand side and subtract 10 from both sides:
$28 y = - 7$ $28y=-7$ by dividing both sides by 28, we get:
$y = - \frac{1}{4}$ $y=-1/4$

By substituting this value of y into the $x = 6 y + 2$ $x=6y+2$ equation, we get:
$x = 6 (- \frac{1}{4}) + 2$ $x=6(-1/4)+2$
$x = - \frac{3}{2} + 2$ $x=-3/2+2$
$x = \frac{1}{2}$ $x=1/2$
Therefore, our answer is the coordinate point $(\frac{1}{2}, - \frac{1}{4})$ $(1/2, -1/4)$

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How do you solve the following system?: $- x + 6 y = - 2, 5 x - 2 y = 3$ $-x+6y= - 2 , 5x - 2y= 3$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system?: −x+6y=−2,5x−2y=3 -x+6y= - 2 , 5x - 2y= 3

1 Answer

Explanation:

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Impact of this question

How do you solve the following system?: $- x + 6 y = - 2, 5 x - 2 y = 3$ $-x+6y= - 2 , 5x - 2y= 3$