How do you solve the following system: $x + y = 4, x - 10 y = 10$ $x+y=4 , x-10y=10$ ?

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How do you solve the following system: $x + y = 4, x - 10 y = 10$ $x+y=4 , x-10y=10$ ?

1 Answer

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Answer 1 · 2018-03-23T15:44:45

$(x, y) = (\frac{50}{11}, - \frac{6}{11})$ $(x,y)=(50/11,-6/11)$

Explanation:

$y = 4 - x$ $y=4-x$ solve for y in terms of x
$x - 10 (4 - x) = 10$ $x-10(4-x)=10$ plug into other equation
$x - 40 + 10 x = 10$ $x-40+10x=10$ distribute
$11 x = 50$ $11x=50$
$x = \frac{50}{11}$ $x=50/11$
$y = \frac{44}{11} - \frac{50}{11}$ $y=44/11-50/11$
$y = - \frac{6}{11}$ $y=-6/11$

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How do you solve the following system: $x + y = 4, x - 10 y = 10$ $x+y=4 , x-10y=10$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system: x+y=4,x−10y=10x+y=4 , x-10y=10 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following system: $x + y = 4, x - 10 y = 10$ $x+y=4 , x-10y=10$ ?