How do you solve the following system: #x+y=4 , x-10y=10 #? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer jk.13 Mar 23, 2018 #(x,y)=(50/11,-6/11)# Explanation: #y=4-x# solve for y in terms of x #x-10(4-x)=10# plug into other equation #x-40+10x=10# distribute #11x=50# #x=50/11# #y=44/11-50/11# #y=-6/11# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1410 views around the world You can reuse this answer Creative Commons License