How do you solve $y = 2 x + 3$ $y=2x+3$ and $y = 3 x + 1$ $y=3x+1$ using substitution?

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How do you solve $y = 2 x + 3$ $y=2x+3$ and $y = 3 x + 1$ $y=3x+1$ using substitution?

1 Answer

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Answer 1 · 2016-12-19T15:45:22

I found:
$x = 2$ $x=2$
$y = 7$ $y=7$

Explanation:

Take the first equation and substitute it into the second for $y$ $y$ :
$2 x + 3 = 3 x + 1$ $color(red)(2x+3)=3x+1$
solve for $x$ $x$ :
$3 x - 2 x = 3 - 1$ $3x-2x=3-1$
$x = 2$ $x=2$
substitute this value back into the first equation:
$y = 2 \cdot 2 + 3 = 7$ $y=2*color(red)(2)+3=7$

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How do you solve $y = 2 x + 3$ $y=2x+3$ and $y = 3 x + 1$ $y=3x+1$ using substitution?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve y=2x+3y=2x+3 and y=3x+1y=3x+1 using substitution?

1 Answer

Explanation:

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Impact of this question

How do you solve $y = 2 x + 3$ $y=2x+3$ and $y = 3 x + 1$ $y=3x+1$ using substitution?