How do you solve #y=2x+3# and #y=3x+1# using substitution?

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How do you solve #y=2x+3# and #y=3x+1# using substitution?

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Answer 1 · 2016-12-19T15:45:22

I found:
#x=2#
#y=7#

Explanation:

Take the first equation and substitute it into the second for #y#:
#color(red)(2x+3)=3x+1#
solve for #x#:
#3x-2x=3-1#
#x=2#
substitute this value back into the first equation:
#y=2*color(red)(2)+3=7#

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How do you solve #y=2x+3# and #y=3x+1# using substitution?

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