How do you solve the following system: $3 x + 2 y = 0, - 5 x - y = 14$ $3x+2y =0, -5x − y = 14$ ?

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Answer 1 · 2018-06-04T04:31:29

$x = - 4$ $x=-4$

$y = 6$ $y=6$

${(3x+2y=0), (-5x-y=14):}$

Do

$3x+2y=0$
$2(-5x-y=14)$

$3x+2y=0$
$-10x-2y=28$

Add the two equations

$-7x=28$

So

$x=28/-7$

$x=-4$

Use $x = -4$ in the first equation

$3(-4)+2y=0$

$-12+2y=0$

$2y=12$

$y=12/2=6$

How do you solve the following system: 3x+2y =0, -5x − y = 14 3x+2y=0,−5x−y=143x+2y =0, -5x − y = 14 ?