How do you solve $2x + y = 1$ and $4x + 2y = -2$ using substitution?

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How do you solve $2x + y = 1$ and $4x + 2y = -2$ using substitution?

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Answer 1 · 2017-05-19T23:11:48

Solve the first equation for $y$ and put it into the second equation.

Explanation:

We're going to have to plug one equation into the other if we want to solve for $x$ and $y$ . First, we'll take the first equation and subtract $2x$ from each side so that the equation is written in terms of $y$ :

$y=-2x+1$

Next, we substitute the $y$ in the second equation with the first equation and solve for $x$ :

$4x+2(2x+1)=-2$
$4x+4x+2=-2$
$8x+2=-2$
$8x=-4$
$x=-1/2$

To solve for $y$ , let's take our first equation and plug in our answer for $x$ :

$y=-2(-1/2)+1$
$y=1+1$
$y=2$

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How do you solve $2x + y = 1$ and $4x + 2y = -2$ using substitution?

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How do you solve $2x + y = 1$ and $4x + 2y = -2$ using substitution?