How do you solve the following system: $-2x + 5y = 20, 3x+y=8$ ?

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Answer 1 · 2016-03-06T01:58:33

You substitute x with zero, then y with zero.

You substitute x with zero, then you solve the equation, and do the same with y. Do for both equations, then graph(if needed)

How do you solve the following system: -2x + 5y = 20, 3x+y=8 -2x + 5y = 20, 3x+y=8 ?