How do you solve the following system?: $2x + 3y = 1 , 3x − y = 30$

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Answer 1 · 2017-08-02T08:26:08

Arrange equations. $x=91/11$ and $y=-57/11$

Second equation will be rewritten:
$9x - 3y = 90$
$2x + 3y= 1$ (the first equation)

Add these:
$11x = 91$
$x=91/11$

Now you can get y
$2times(91/11) + 3y = 1$

$3y = 1 - 182/11$

$3y= -171/11$

$y= -171/33$

or $y=-57/11$

How do you solve the following system?: 2x + 3y = 1 , 3x − y = 30 2x + 3y = 1 , 3x − y = 30